SOLUTION: How many gallons of 20% anitfreeze should be mixed with 10 gallons of 76% antifreeze to obtain a 55% antifreeze mixture

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Question 902257: How many gallons of 20% anitfreeze should be mixed with 10 gallons of 76% antifreeze to obtain a 55% antifreeze mixture
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
.76(10G) + .20x = .55(10G + x)
.21(10G)/.35 = x