SOLUTION: Suppose you have 6 oz of milk and mix 2 oz of chocolate syrup. Then, you pour out 2 oz of the mixture. How much chocolate syrup remains? I know the answer is 1 1/2, but can you p

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Suppose you have 6 oz of milk and mix 2 oz of chocolate syrup. Then, you pour out 2 oz of the mixture. How much chocolate syrup remains? I know the answer is 1 1/2, but can you p      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 901541: Suppose you have 6 oz of milk and mix 2 oz of chocolate syrup. Then, you pour out 2 oz of the mixture. How much chocolate syrup remains? I know the answer is 1 1/2, but can you please explain? Thanks so much!
Found 2 solutions by richwmiller, josgarithmetic:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
You are adding 6+2=8 oz of mixture
2/8=1/4 is syrup
6/8=3/4 is milk
1/4*8=2 oz
3/4*8=6 oz
You toss 2 oz mixture.
You now have 6 oz of mixture which is still 3/4 milk and 1/4 syrup
1/4*6=1.5 oz syrup
3/4*6=4.5 oz milk






Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Analyze the process step-by-step.

Mixture: 6 units milk plus 2 units of chocolate syrup.
Fraction of chocolate syrup is 2%2F%286%2B2%29=1%2F4.

Remove 2 units of mixture.
This leaves 6 units of MIXTURE.
Remember, this mixture is 1%2F4 chocolate syrup.

How much chocolate syrup remains as part of the mixture?
6%2A%281%2F4%29=%282%2A3%29%2F%282%2A2%29=3%2F2=1%261%2F2 units of chocolate syrup.