SOLUTION: Hi. Here's the textual form of the problem; How many liters of a 6 \% solution of salt should be added to a 22 \% solution in order to obtain 544 liters of a 13 \% solution?
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Question 900767: Hi. Here's the textual form of the problem; How many liters of a 6 \% solution of salt should be added to a 22 \% solution in order to obtain 544 liters of a 13 \% solution?
The way I've been setting it up is
.06x+.022(544-x)=.13
but my final result ends up being -239.36 liters. I have a feeling that one is way wrong, so I'd appreciate any help you'd be willing to offer!
Thanks in advance- the service you guys provide is amazing. Thank you!
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Hi. Here's the textual form of the problem; How many liters of a 6 \% solution of salt should be added to a 22 \% solution in order to obtain 544 liters of a 13 \% solution?
The way I've been setting it up is
.06x+.022(544-x)=.13
but my final result ends up being -239.36 liters. I have a feeling that one is way wrong, so I'd appreciate any help you'd be willing to offer!
Thanks in advance- the service you guys provide is amazing. Thank you!
Let amount of 6% solution to be mixed, be S
Then amount of 22% solution to be mixed = 544 - S
Therefore, .06S + .22(544 – S) = .13(544)
.06S + 119.68 - .22S = 70.72
.06S - .22S = 70.72 – 119.68
- .16S = - 48.96
S, or amount of 6% solution = , or L
