You can put this solution on YOUR website! How many liters of a 20% solution of a chemical should be mixed with 15l of a 50% solution to get a 30% solution ?
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Equation:
active + active = active
0.20x + 0.50*151 = 0.30(x+151)
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20x + 50*151 = 30x + 30*151
-10x = -20*151
x = 151/2 = 75.5 liters (amt of 20% solution needed)
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Cheers,
Stan H.
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