SOLUTION: a chemist has two solutions of HNO3. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 70 liters of a 32%

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Question 894173: a chemist has two solutions of HNO3. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 70 liters of a 32% solution
x=40%=0.4x
25%=70-x
0.25(70-x)
0.4x+0.25(70-x)=32
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Maybe the percents are as mass per volume???

If this is the case, then like this to solve:

u = ml of 25%
v = ml of 40%

%2825u%2B40v%29%2F70=32 and u%2Bv=70.

The concentration equation is simplifiable to 5u%2B8v=448.

Solve the system, highlight_green%28system%285u%2B8v=448%2Cu%2Bv=70%29%29.