SOLUTION: What quantity of 75 per cent acid solution must be mixed with a 20 per cent solution to produce 440 mL of a 50 per cent solution?

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Question 892649: What quantity of 75 per cent acid solution must be mixed with a 20 per cent solution to produce 440 mL of a 50 per cent solution?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by MathTherapy(10552) About Me  (Show Source):
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What quantity of 75 per cent acid solution must be mixed with a 20 per cent solution to produce 440 mL of a 50 per cent solution?


Let amount of 75% solution to be mixed, be S

Then amount of 20% solution is: 440 – S

Thus, we have: .75(S) + .2(440 – S) = .5(440)

.75S + 88 - .2S = 220

.75S - .2S = 220 – 88

.55S = 132

S, or amount of 75% solution to be mixed = 132%2F.55, or highlight_green%28240%29 mL

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