SOLUTION: A chemist has three solutions containing a given acid. First solution contains 10% of the acid solution; second solution has 30%, and the third one has 50%. He/she desires to use t
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Question 891846: A chemist has three solutions containing a given acid. First solution contains 10% of the acid solution; second solution has 30%, and the third one has 50%. He/she desires to use the three solutions to obtain a mixture of 50 L containing 32% of acid by using twice the 50% solution than 30% solution. How many liters from each solution are to be used? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = liters of the 30% solution used = liters of the 50% solution used
Let = liters of the 10% solution used
-------------------------------------- = liters of acid in 30% solution liters of acid in 50% solution = liters of acid in 10% solution
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(1)
(2)
(2)
-----------------------
(1)
(1)
(1)
-----------------------
Subtract (2) from (1)
(1)
(2)
and
and, since
(2)
(2)
(2)
(2)
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11 liters of the 30% solution should be used
22 liters of the 50% solution should be used
17 liters of the 10% solution should be used
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check:
(1)
(1)
(1)
(1)
OK
