Question 886501: How many liters of a 15% acid solution must be mixed with 5 liters of a 25% acid solution to give a 20% solution? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many liters of a 15% acid solution must be mixed with 5 liters of a 25% acid solution to give a 20% solution?
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Equation:
acid + acid = acid
0.15x + 0.25*5 = 0.20(x+5)
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15x + 25*5 = 20*x + 20*5
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-5x = -5*5
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x = 5 liters (amt of 15% solution needed)
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Cheers,
Stan H.
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