SOLUTION: A solution that is 50% alcohol is mixed with a solution that is 40% alcohol in order to make 50 liters of a solution that is 46% alcohol. How many liters of

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Question 880752: A solution that is 50% alcohol is mixed with a solution that is 40% alcohol in order to make
50 liters of a solution that is 46% alcohol. How many liters of the 40% solution and how
many liters of the 50% solution should be used?



Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
percent ---------------- quantity
alcohol I 40.00% ---------------- x liters
alcohol ii 50.00% ------ 50 - x liters
Mixture 46.00% ---------------- 50
Total 50 liters
40.00% x + 50.00% ( 50 - x ) = 46.00% * 50
40 x + 50 ( 50 - x ) = 2300
40 x + 2500 - 50 x = 2300
40 x - 50 x = 2300 - -2500
-10 x = -200
/ -10
x = 20 liters 40.00% alcohol I
30 liters 50.00% alcohol ii

m.ananth@hotmail.ca


Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = liters of 50% solution needed
Let +b+ = liters of 40% solution needed
----------------------------------------------
(1) +a+%2B+b+=+50+
(2) +%28+.5a+%2B+.4b+%29+%2F+50+=+.46+
-------------------------------------
(2) +.5a+%2B+.4b+=+.46%2A50+
(2) +.5a+%2B+.4b+=+23+
(2) +5a+%2B+4b+=+230+
---------------------------
Multiply both sides of (1) by +4+
and subtract (1) from (2)
(2) +5a+%2B+4b+=+230+
(1) +-4a+-+4b+=+-200+
+a+=+30+
and, since
(1) +a+%2B+b+=+50+
(1) +b+=+20+
30 liters of 50% solution is needed
20 liters of 40% solution is needed
check:
(2) +%28+.5%2A30+%2B+.4%2A20+%29+%2F+50+=+.46+
(2) +%28+15+%2B+8+%29+%2F+50+=+.46+
(2) +23+=+.46%2A50+
(2) +23+=+23+
OK