SOLUTION: Chris needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 54% solution. How many millileters of each solution must Chris use? mililite

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Chris needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 54% solution. How many millileters of each solution must Chris use? mililite      Log On

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Question 858246: Chris needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 54% solution. How many millileters of each solution must Chris use?
mililiters of 20% solution
mililiters of 60% solution
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
Let the volume of 20% sol be x
Then volume of 60% sol is 200 - x
Alcohol in 20% sol = 0.2+%2A+x
Alcohol in 60% sol = 0.6+%2A+%28200+-+x%29+=+120+-+0.6+%2A+x
If the final solution is of 54% concentration, it means the volume of alcohol in it
= 200+%2A+0.54+=+108 
So we have the equation
0.2+%2A+x+%2B+120+-+0.6%2Ax+=+108
0.4+%2A+x+=+12
x+=+30
So he takes 30 ml of 20% alcohol and 170 ml of 60% alcohol
Check:
30 ml contains 30 * 20% = 6 ml of alcohol
170 ml contains 170 * 60% = 102 ml of alcohol
Total alcohol = 6 + 102 = 108 which is 54% of 200 ml. Correct!

:)