Question 856786: how many liters of 20% antifreeze solution and a 40% antifreeze solution must be mixed to make 10 liters of a 28% antifreeze solution? Found 2 solutions by josgarithmetic, lwsshak3:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! how many liters of 20% antifreeze solution and a 40% antifreeze solution must be mixed to make 10 liters of a 28% antifreeze solution?
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let x=amt of 20% antifreeze solution to mix
10-x=amt of 40% antifreeze solution to mix
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20%x+40%(10-x)=28%*10
.20x+4-.40x=2.8
.20x=1.2
x=6
10-x=4
amt of 20% antifreeze solution to mix=6 liters
amt of 40% antifreeze solution to mix=4 liters
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