SOLUTION: 1 solution is 23 acid and another solution is 57 percent acid how many milliliters of each should be mixed to obtain 34 millimeters of a solution that is 32 percent acid
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Question 855231: 1 solution is 23 acid and another solution is 57 percent acid how many milliliters of each should be mixed to obtain 34 millimeters of a solution that is 32 percent acid Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1 solution is 23 acid and another solution is 57 percent acid how many milliliters of each should be mixed to obtain 34 millimeters of a solution that is 32 percent acid
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Quantity Eq:: t + f = 34 ml
Acid Eq:: 0.23t + 0.57f = 0.32*34
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Modify for elimination:
23t + 23f = 23*34
23t + 57f = 32*34
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34f = 9*34
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f = 9 ml (amt. of 57% solution needed)
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t = 34-9 = 25 ml (amt. of 23% solution needed)
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Cheers,
Stan H.
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You can put this solution on YOUR website! Let = ml of 23% solution needed
Let = ml of 57% solution needed
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(1)
(2)
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(2)
(2)
(2)
Multiply both sides of (1) by
and subtract (1) from (2)
(2)
(1)
and
(1)
(1)
(1)
25 ml of 23% solution is needed
9 ml of 57% solution is needed
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check:
(2)
(2)
(2)
OK
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