SOLUTION: I need to calculate a mixture of 2 products: Mixture A = 58% of B + 42% of C A B C are all volumes in liters B is a known value. How do I calculate C

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Question 846462: I need to calculate a mixture of 2 products:
Mixture A = 58% of B + 42% of C
A B C are all volumes in liters
B is a known value.
How do I calculate C

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
A= volume of mixture A
B= volume of product B in mixture A
C= volume of product C in mixture A
Mixture A is made of 58% of product B and 42% of product C.
We assume that volumes are additive (or very nearly so),
meaning that A=B%2BC .
B is 58% of A, so B=%2858%2F100%29%2AA or B=0.58A
C is 42% of A, so C=%2842%2F100%29%2AA or C=0.42A

With B=0.58A and C=0.42A ,
given any one of the volumes, you can calculate the other two volumes.
If you know B ,
B=0.58A --> B%2F0.58=A --> highlight%28A=B%2F0.58%29 .
Then,
system%28C=0.42A%2CA=B%2F0.58%29 --> C=0.42%28B%2F0.58%29 --> highlight%28C=0.42%2AB%2F0.58%29 or highlight%28C=%2842%2F58%29%2AB%29
That can be calculated as approximately C=0.724%2AB%29 .