SOLUTION: How many liters of a 50% acid solution must be added to 16 liters of a 30% acid solution to produce a 35% acid solution? I put (.50)(L)+ (.30)(16)=.35(16+L) multiplied each by

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Question 845977: How many liters of a 50% acid solution must be added to 16 liters of a 30% acid solution to produce a 35% acid solution?
I put (.50)(L)+ (.30)(16)=.35(16+L)
multiplied each by 100
50L + 48000 = 560 + 35L
50L - 35L + 4800 = 560
15L + 4800 = 560
15L = -4240
L = -282.6
I know I am way off and need assistance.
Found 2 solutions by Fombitz, richwmiller:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You multiplied your second term twice.
50L%2B30%2816%29=35%28L%2B16%29
50L%2B480=35L%2B560
15L=120
L=120%2F15=8

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Your initial equation is fine
(.50)(L)+ (.30)(16)=.35(16+L)
You messed up multiplying by 100
50L + 30*16 = 35*16 + 35L
50L + 480 = 560 + 35L
15L=80
L=80/15
L=5 1/3=5.33333
without multiplying by 100
(.50)(L)+ (.30)(16)=.35(16+L)
.50L+ 4.8=5.6+.35L
0.15 L=0.80
L=.80/.15
L = 5.33333