SOLUTION: Hi, I am struggling with an application problem that has to deal with mixtures.
To make a flour mixture, a miller combined soybeans that cost $8.50 per bushel with wheat that c
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To make a flour mixture, a miller combined soybeans that cost $8.50 per bushel with wheat that c
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Question 839264: Hi, I am struggling with an application problem that has to deal with mixtures.
To make a flour mixture, a miller combined soybeans that cost $8.50 per bushel with wheat that cost $4.50 per bushel. How many bushels of each were used to make a mixture of 800 bushels costing $5.50 per bushel? Found 2 solutions by josmiceli, ankor@dixie-net.com:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = bushels of soybeans needed
Let = bushels of wheat needed = cost of bushels of soybeans = cost of bushels of wheat
----------------------------------------
(1)
(2)
-------------------------------
(2)
(2)
(2)
(2)
Multiply both sides of (1) by
and subtract (1) from (2)
(2)
(1)
and, since
(1)
(1)
(1)
200 bushels of soybeans are needed
600 bushels of wheat are needed
---------------------------------
check:
(2)
(2)
(2)
(2)
(2)
OK
You can put this solution on YOUR website! To make a flour mixture, a miller combined soybeans that cost $8.50 per bushel with wheat that cost $4.50 per bushel.
How many bushels of each were used to make a mixture of 800 bushels costing $5.50 per bushel?
:
Let x = amt of soybean meal
the final total is to be 800 bu, therefore:
(800-x) = amt of wheat flour required
:
The mixture equation
8.50x + 4.50(800-x) = 5.50(800)
8.5x + 3600 - 4.5x = 4400
8.5x - 4.5x = 4400 - 3600
4x = 800
x = 800/4
x = 200 bu of soy meal
then
800 - 200 = 600 bu of wheat flour
