SOLUTION: If we want 25 mL of 18% alcohol diluted from 70% alcohol, we must do two steps: a) Solve this equation for x: 70% x = 18% (25 mL) x is the amount (in mL) of 70% alcohol needed.

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: If we want 25 mL of 18% alcohol diluted from 70% alcohol, we must do two steps: a) Solve this equation for x: 70% x = 18% (25 mL) x is the amount (in mL) of 70% alcohol needed.       Log On

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Question 838671: If we want 25 mL of 18% alcohol diluted from 70% alcohol, we must do two steps:
a) Solve this equation for x: 70% x = 18% (25 mL)
x is the amount (in mL) of 70% alcohol needed.
b) You want a total of 25 mL solution, so now subtract x from 25mL to determine the
amount of water needed.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
25 mL of 18% alcohol(82% water) diluted from 70% alcohol(30% water)
Let x represent the ml of water added to do this
water = water
.30%2A%2825-x%29+%2B+x+=+.82%2A25ml%0D%0A+%7B%7B%7B.70x+=+.52%2A25
x+=+%28.52%2A25%29%2F.70+