SOLUTION: A 60% alcohol solution is to be mixed with a 42% alcohol solution. How many liters of the 60% solution should be used to make 30 liters of a 54% alcohol solution?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A 60% alcohol solution is to be mixed with a 42% alcohol solution. How many liters of the 60% solution should be used to make 30 liters of a 54% alcohol solution?
Log On
Question 838374: A 60% alcohol solution is to be mixed with a 42% alcohol solution. How many liters of the 60% solution should be used to make 30 liters of a 54% alcohol solution? Found 3 solutions by josgarithmetic, stanbon, ewatrrr:Answer by josgarithmetic(39616) (Show Source):
You can put this solution on YOUR website! A 60% alcohol solution is to be mixed with a 42% alcohol solution. How many liters of the 60% solution should be used to make 30 liters of a 54% alcohol solution?
--------
Equation:
alch + alch = alch
0.60x + 0.42(30-x) = 0.54*30
-------------------------
60x + 42*20 - 42x = 54*30
---------
18x = 12*30
x = 20 liters (amt. of 60% solution needed)
30-x = 10 liters (amt. of 42% solution needed)
--------------------
Cheers,
Stan H.
-------------------