Question 832755: How many mg of metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing78% nickel? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many mg of metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing78% nickel?
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Equation:
nick + nick = nick
0.45x + 1*6 = 0.78(x+6)
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45x + 100*6 = 78x + 78*6
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-33x = -22*6
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x = (2/3)6
x = 4 mg (amt. of pure nickel needed)
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Cheers,
Stan H.
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