SOLUTION: A mechanic is working on a car with a 20-qt radiator containing a 60% antifreeze solution. How much of the solution should he drain and replace with pure water to get a solution th

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Question 831546: A mechanic is working on a car with a 20-qt radiator containing a 60% antifreeze solution. How much of the solution should he drain and replace with pure water to get a solution that is 50% antifreeze?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = quarts of solution that musty be drained
and replaced with pure water
+.6x+ = quarts of pure antifreeze in the solution
that is drained from radiator
+.6%2A20+=+12+ = quarts of pure antifreeze originally
in the radiator
-------------------------
+%28+12+-+.6x+%29+%2F+20+=+.5+
+12+-+.6x+=+.5%2A20+
+12+-+.6x+=+10+
+.6x+=+12+-+10+
+.6x+=+2+
+x+=+3.333+
3.333 quarts of the solution should he drained and replaced
with pure water to get a solution that is 50% antifreeze
-------------------
check answer:
+.6%2A3.333+=+2+ quarts of pure antifreeze is drained
There is +.6%2A20+-+2+
+12+-+2+=+10+ quarts of pure antifreeze left
The concentration after the 4 quarts of water is
poured in is:
+10%2F20+=+.5+
+.5%2A100+ = 50% antifreeze
OK