SOLUTION: a tank holds 20 L of a chemical solution, with a current strength of 60%. how much must be replaced with 100% solution to get a final strength of 80%

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: a tank holds 20 L of a chemical solution, with a current strength of 60%. how much must be replaced with 100% solution to get a final strength of 80%      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 831055: a tank holds 20 L of a chemical solution, with a current strength of 60%. how much must be replaced with 100% solution to get a final strength of 80%
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This is only a partial explanation for solving the example problem.

Remove and replace a volume quantity, v liters of the solution in the tank.
20%2A0.60-v%2A0.60 is the amount of chemical ( as if 100%) in the tank; then will add to maintain the original volume with the pure solution at 100% strength, so you will have 20%2A0.60-v%2A0.60%2Bv%2A1.00 amount of pure chemical in the tank.

Working with the accounting of pure chemical in the solution in the tank,
20%2A0.6-v%2A0.6%2Bv%2A1
20%2A0.6-v%2A0.6%2Bv
20%2A0.6%2Bv-0.6%2Av
20%2A0.6%2B%281-0.6%29v
20%2A%280.6%29%2B%280.4%29v, amount of resulting pure chemical in the tank