SOLUTION: We have 500 ml of soda solution (density = 1.08 g/ml and 8% (m/m) soda). We need to make a soda solution which contains 15% (m/m) soda. How much of crystal soda (62.9% (m/m) wa

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: We have 500 ml of soda solution (density = 1.08 g/ml and 8% (m/m) soda). We need to make a soda solution which contains 15% (m/m) soda. How much of crystal soda (62.9% (m/m) wa      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 828932: We have 500 ml of soda solution (density = 1.08 g/ml and 8% (m/m) soda).
We need to make a soda solution which contains 15% (m/m) soda.
How much of crystal soda (62.9% (m/m) water) do we need to add?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Starter amount of soda solution is 500*1.08 grams, 540 grams of 8% m/m soda.

You want to add some x amount of 62.9% m/m WATER, which is 37.1% SODA, to the 540 grams to get 15% m/m soda. To this extent, we are no longer interested in volumes.

I said this, which was WRONG------------------------------------
%28540%2A8%2Bx%2A62.9%29%2F%28x%2B540%29=15
Solve for x, the grams of the "Crystal Soda" 62.9% m/m to add.
----------------------------------------------------------------

I should have said this, much more correct---------------------
%28540%2A8%2B37.1%2Ax%29%2F%28x%2B540%29=15
Solve for x, the grams of "Crystal Soda", 62.9% m/m water, 37.1% SODA
---------------------------------------------------------------

One would imagine that Crystal Soda is the name of a concentrated carbonated drink. On the other hand, 8% sodium hydroxide has a density very close to what you gave. 62.9%, concentration of the water, 37.1% m/m of SODA.