Question 827158: What amounts of 50% pure silver and 60% pure silver should be mixed to obtain 14 grams of 58% pure silver? Found 2 solutions by josgarithmetic, JBarnum:Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website! Two known concentrations of one substance, both quantities of the materials unknowns; but amount of mixture known, and result concentration known.
See in my profile, the lesson link, for "Mixing two concentrations for known amount of mixture "
You can put this solution on YOUR website! im no good at mixing problems but seen how its already answerted id give u my closest guess to guess n check version....
theres 14 total grams of this silver mixture and since 58% is closer to 60% then 50% there will be alot more of the 60% then of the 50% used
i started with 2 grams of 50% and 12 grams of 60% which comes out to 58.571428...repeating
so i upped it to 2.5grams and 11.5grams which comes to
58.21428571428...
so i upped it to grams and grams which comes to
exactly 58%
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