SOLUTION: A man buys milk at 60 P per liter, adds 1/3rd of water to it and sells the mixture at 72 P per liter. The profit percentage is.......?

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Question 826170: A man buys milk at 60 P per liter, adds 1/3rd of water to it and sells the mixture at 72 P per liter. The profit percentage is.......?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
He bought some B liters of milk at 60 P money units, and added 1%2F3%29B liters of water. The mixture is B%2B%281%2F3%29B liters containing the B liters of milk.

His revenue upon selling all of his mixture is B%281%2B1%2F3%29%2A72 P money units.

Summarize:
Cost = B%2A60 P units
Revenue = B%281%2B1%2F3%29%2A72 P units
Profit = Revenue+-+Cost+=+B%284%2F3%29%2A72-B%2A60+=+B%28%284%2F3%2972-60%29 of P money units

Profit percentage based on revenue woould be 100%2A%28B%28%284%2F3%2972-60%29%29%2F%28B%281%2B1%2F3%29%2A72%29, if that was what you meant; which you can simplify and compute.

If you meant, based on cost, then divide profit by cost, and then multiply by 100.