SOLUTION: How many liters of 40% acid solution must be mixed with 10 liters of a 65% acid solution to get a 45% acid solution?

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Question 823038: How many liters of 40% acid solution must be mixed with 10 liters of a 65% acid solution to get a 45% acid solution?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Assign Variables:
v = How many liters of 40% acid
L = 40%, the low concentration of acid
R = 10 liters of 65%, higher concentrated acid
H = 65% the higher concentration acid
T = 45%, the target concentration of acid wanted

{pure amount of acid}/{amount of blend}={resulting concentration}

Pure+Acid+=+L%2Av%2BH%2AR, which is 100 times larger because direct percents are used;

Amount+of+Blend+=+v%2BR

Equation to solve:
'
%28Lv%2BHR%29%2F%28v%2BR%29=T
Solve for the UNKNOWN variable, v.
Replace all other variables with their given values and compute v.