SOLUTION: How much of a 10 liter 30% acid solution must be replaced with pure acid to obtain 10 liters of a 50% solution?

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Question 821558: How much of a 10 liter 30% acid solution must be replaced with pure acid to obtain 10 liters
of a 50% solution?
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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30(10 - x) + 100x = 50*10
300 - 30x + 100x = 500
300 + 70x = 500
70x = 200
x = 2.8571429
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answer:
replace 2.857 liters
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