SOLUTION: How much 2% acid must be mixed with 10% acid to obtain 2,000 ml of 8% acid?

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Question 820053: How much 2% acid must be mixed with 10% acid to obtain 2,000 ml of 8% acid?
Answer by jerryguo41(197) About Me  (Show Source):
You can put this solution on YOUR website!
x=ml of 10% acid in solution
y=ml of 2% acid in solution
percentage(amount)+percentage(amount)=total percentage(total amount)
.1x%2B.02y=2000%28.08%29
.1x%2B.02y=160
Substitute y=2000-x
.1x%2B.02%282000-x%29=160
.1x%2B40-0.02x=160
0.08x=120
x=1500
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y=2000-x
y=2000-1500
y=500
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1500 mL of 10% acid
500 mL of 2% acid
creates 2000 mL of 8% acid