Question 819020: A chemist has 100 liters of 30% sodium chloride solution. She intends to drain a certain number of liters and replace with a more concentrated solution.
a) How much of this solution should she drain and replace with 80% sodium chloride if she wants a 55% sodium chloride solution?
Found 4 solutions by josgarithmetic, stanbon, MathTherapy, richwmiller:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! NO!
Where did this problem come from?
At the dubious concentration of 30% sodium chloride, the solution cannot be made more concentrated.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A chemist has 100 liters of 30% sodium chloride solution. She intends to drain a certain number of liters and replace with a more concentrated solution.
a) How much of this solution should she drain and replace with 80% sodium chloride if she wants a 55% sodium chloride solution?
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sc - sc + sc = sc
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0.30*100 - 0.30x + 1*x = 0.80*100
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Multiply thru by 100 to get::
30*100 - 30x + 100x = 80*100
70x = 50*100
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x = 7.14 liters (amt of liquid to remove and replace.
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Cheers,
Stan H.
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Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
A chemist has 100 liters of 30% sodium chloride solution. She intends to drain a certain number of liters and replace with a more concentrated solution.
a) How much of this solution should she drain and replace with 80% sodium chloride if she wants a 55% sodium chloride solution?
Amount to be drained from 100 L of 30% CS, and replaced with 80% CS to get 55% SC:  L
You can do the check!!
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Answer by richwmiller(17219)  (Show Source):
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