SOLUTION: A man has 10 gallons of a 50% sulphuric acid mixture, and 20 gallons of a 20% solution, and 5 gallons of a 10% solution. He wants to use up all the 10% solution and make 15 gallons
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Question 818791: A man has 10 gallons of a 50% sulphuric acid mixture, and 20 gallons of a 20% solution, and 5 gallons of a 10% solution. He wants to use up all the 10% solution and make 15 gallons of 30% solution. How much of each solution should he use? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! 50x + 20y + 10z = 30(15)
50x + 20y + 10z = 450
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z = 5
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x + y + z = 15
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system of linear equations:
50x + 20y + 10z = 450
x + y + z = 15
z = 5
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copy and paste the above standard form linear equations in to this solver:
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get result from solver:
x= 6.66666667
y= 3.33333333
z= 5
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answer:
x= 6 + 2/3 gal 50% solution
y= 3 + 1/3 gal 20% solution
z= 5 gal 10% solution
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