SOLUTION: How many liters of a 10% solution of acid should mixed with 60% solution of acid to obtain a 20 liters of 50% solution? Please show me a step by step guide through because I wa

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many liters of a 10% solution of acid should mixed with 60% solution of acid to obtain a 20 liters of 50% solution? Please show me a step by step guide through because I wa      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 815286: How many liters of a 10% solution of acid should mixed with 60% solution of acid to obtain a 20 liters of 50% solution?
Please show me a step by step guide through because I want understand the material to pass a quiz on these types of questions.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
100*{amount of pure acid}/{amount of solution}={percentage concentration}

Let u = how many liters of the 10% acid
Let v = how many liters of the 60% acid
Wanting 20 liters of acid solution, u%2Bv=20.

Using the percentage concentrations,
10u%2B60v is how much of the actual pure acid; this is in scaled-up form, since the percent concentrations are 100 times larger than their fractional meanings.

highlight%28%2810u%2B60v%29%2F20=50%29 and highlight%28u%2Bv=20%29;
Solve the system for u and v.