Question 815024: Car A leaves home at 40 m/h.Four hours later car B leaves from a house that is 700 miles away headed towards car A at 50 m/h.How long will it take before the two cars meet?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! s = d / t
d = s * t
t = d / s
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when b leaves a has already traveled:
d = 40 * 4 = 160 miles
so when b leaves, the distance between a and b is:
700 - 160 = 540 miles
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the closing speed of the two cars is:
40 + 50 = 90 mph
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when the cars meet they will have covered 540 miles between both cars, at a closing speed of 90 mph, so:
t = 540 / 90 = 6 hours
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Answer:
the cars will meet:
6 hours after b leaves
10 hours after a leaves (because a left 4 hours earlier than b)
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