SOLUTION: find a number that is twice as far from 40 as it is from 73

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Question 814694: find a number that is twice as far from 40 as it is from 73
Found 3 solutions by LinnW, ewatrrr, Amilasor:
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
2(40-x)=73-x
80 -2x = 73 - x
add 2x to each side
80 = 73 -x + 2x
80 = 73 +x
Subtract 73 from each side
80 - 73 = 73 + x -73
7 = x
Notice
2( 40 - 7 ) = 73 - 7
2(33) = 73 -7
66 = 66

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

find a number that is twice as far from 40 as it is from 73

 40___________________x_____________73

Question states***

 (x-40) = 2(73-x)

   3x = 186

    x =  62

CHECKING our Answer***

(62 -40) = 22 = 2(73-62)



 40___________________62___________73

Answer by Amilasor(2) About Me  (Show Source):
You can put this solution on YOUR website!
2(x-73) = 40-x
2x-146=40-x
3x=186
x=62