SOLUTION: x pounds of candy valued at $3.50 per pound is mixed with y pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find x and y, the
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: x pounds of candy valued at $3.50 per pound is mixed with y pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find x and y, the
Log On
Question 814538: x pounds of candy valued at $3.50 per pound is mixed with y pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find x and y, the number of pounds of each type. I've tried this several different ways and can't see to do it right. This is due tomorrow and I'm freaking out about what I'm doing wrong. Found 2 solutions by mananth, josgarithmetic:Answer by mananth(16946) (Show Source):
1.00 x + 1.00 y = 10.00 .............1
Total value
3.50 x + 4.30 y = 40.00 .............2
Eliminate y
multiply (1)by -4.30
Multiply (2) by 1.00
-4.30 x -4.30 y = -43.00
3.50 x + 4.30 y = 40.00
Add the two equations
-0.80 x = -3.00
/ -0.80
x = 3.75
plug value of x in (1)
1.00 x + 1.00 y = 10.00
3.75 + y = 10.00
y = 10.00 -3 3/4
y = 6.25
y = 6.25
x= 3.75 quantity candy I
y= 6.25 quantity candy II
m.ananth@hotmail.ca
cool
You can put this solution on YOUR website! Use the information in the first sentence to account for cost.
The second equation shown here is for the described PRICE for the candy mixture. The 10 pound mixture is supposed to have a price of 4 dollars per pound. See, COST of mixture divided by POUNDS of mixture is the price in dollars per pound.
You need one more equation so you can solve for both the values of x and y. , which accounts for the number of pounds of each of the differently priced candies.
You now just need to solve this system for x and y:
and