SOLUTION: Sketch the titration curve (volume versus pH) for the addition of 0.50 M NaOH to 20.0 mL of 0.20 M HCl. Mark clearly the starting point and the half-equivalence point and the pH

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Sketch the titration curve (volume versus pH) for the addition of 0.50 M NaOH to 20.0 mL of 0.20 M HCl. Mark clearly the starting point and the half-equivalence point and the pH      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 813420: Sketch the titration curve (volume versus pH) for the addition of 0.50 M NaOH to 20.0 mL of 0.20 M HCl.
Mark clearly the starting point and the half-equivalence point and the pH and calculate their values.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The equivalence point volume would be when the moles of added NaOH and already-present HCl match.

0.5v=0.2%2A20
v=0.2%2A20%2F0.5
v=4%2F0.5=4%2A2=8
highlight%28v=8%29 ml.

Titrant volumes less than 8 ml. will keep HCl in excess and the pH will be directly from the excess HCl. Titrant volumes larger than 8 ml. will ensure that NaOH is in excess and so pH will be based on the NaOH present in excess.

Your volume increments to use for data point calculations could be 1 mililiter increments, but you might choose a different increment, or more than just one size increment.