SOLUTION: A farmer mixed gasoline and oil to have 2 gallons of mixture for his chain saw. The mixture was 32 parts gasoline to 1 part oil. How much gasoline must be added to bring the mixt
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Question 813298: A farmer mixed gasoline and oil to have 2 gallons of mixture for his chain saw. The mixture was 32 parts gasoline to 1 part oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil?
My attempt: .32 (2) + 1 (X) = .40 (2 + X)
.64 + X = .8 + .4X
X = .2666 gal of gas to be added
The author says it is .48 gal of gas to be added
Thanks,
Bob
P. S. I am not a student. I am 67 and just trying to keep my brain working.
Hi,
re reply: Great idea!
Yes, the "fraction" 1/33 says the oil is 1/33 of the entire mixture
The 2 gal mixture was 32 parts gasoline to 1 part oil.
How much gasoline must be added to bring the mixture to
40 parts gasoline and 1 part oil?
(32:1 does not say there is 32% gas)
the Oil as a % is easier to work with: 1/33 0r 1/41
As You had let x represent gas added |Cross Multiplying to solve
