SOLUTION: A 20% acid solution is mixed with a 70% acid solution to get 50 liters of a 40% solution. How much of the 70% solution is used? and Going against the current, a boat take

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Question 809730: A 20% acid solution is mixed with a 70% acid solution to get 50 liters of a 40% solution.
How much of the 70% solution is used?
and
Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return trip, it takes 5 hours.
If x = the rate of the boat in still water and y = the rate of the current, which of the following systems could be used to solve the problem?
a.) 6(x - y) = 120 and 5(x + y) = 120
b.) 6(x + y) = 120 and 5(x - y) = 120
c.) 6x - 5y = 120 and x + y = 120

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = liters of 20% solution needed
Let +b+ = liters of 70% solution needed
(1) +a+%2B+b+=+50+
(2) +%28+.2a+%2B+.7b+%29+%2F+50+=+.4+
--------------------------
(2) +.2a+%2B+.7b+=+.4%2A50+
(2) +.2a+%2B+.7b+=+20+
(2) +2a+%2B+7b+=+200+
Multiply both sides of (1) by 2
and subtract (1) from (2)
(2) +2a+%2B+7b+=+200+
(1) +-2a+-2b+=+-100+
+5b+=+100+
+b+=+20+
and, since
(1) +a+%2B+b+=+50+
(1) +a+=+30+
30 liters of 20% solution are needed
20 liters of 70% solution are needed
check:
(2) +%28+.2%2A30+%2B+.7%2A20+%29+%2F+50+=+.4+
(2) +%28+6+%2B+14+%29+%2F+50+=+.4+
(2) +20+=+.4%2A50+
(2) +20+=+20+
OK
----------------------------
(a) is the answer
+d+=+r%2At+
Subtract the rate of the current from the rate of the boat
in still water when going against the current
---------
Add the 2 rates when going with the current