SOLUTION: You need 810 mL of a 30% alcohol solution. On hand, you have a 5% alcohol mixture and a 95% alcohol mixture. How much of each mixture will you need to obtain the desired solution?
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Question 807978: You need 810 mL of a 30% alcohol solution. On hand, you have a 5% alcohol mixture and a 95% alcohol mixture. How much of each mixture will you need to obtain the desired solution?
How much of the 5% solution and how much of the 95% solution do I need? Answer by josgarithmetic(39617) (Show Source):
ASSIGN VARIABLES
L = 5% alcohol
T = 30%, the concentration target
H = 95%, the high concentration material
M = 810 mL, amount of T conc. wanted
u = unknown amount of L material
v = unknown amount of H material
FORMULATE EQUATIONS
and
SOLVE THE SYSTEM FOR u AND v.
You do the steps. The essential part (or maybe half of it) was to form the system of equations. The steps after that are routine.
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