SOLUTION: 2 towns are 100 miles apart. A group of hikers start from each town, and walk the trail towards each other. They meet after a total hiking time of 200 hours. If 1 group travels 2

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Question 806892: 2 towns are 100 miles apart. A group of hikers start from each town, and walk the trail towards each other. They meet after a total hiking time of 200 hours. If 1 group travels 2 1/2 mph faster than the other group, find the rate of each group. My thanks and appreciation to you!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You can think of this as the slower group standing
still and the other group approaching at the
sum of their speeds
Let +s+ = the speed of the slower group in mi/hr
+2.5s+ = the speed of the faster group in mi/hr
-------------------------------------------
+100+=+%28+s+%2B+2.5s+%29%2A200+
+.5+=+s+%2B+2.5s+
+3.5s+=+.5+
+s+=+.1429+ mi/hr
+2.5s+=+.3573+ hrs
------------------
Their speeds are .1429 mi/hr and .3573 mi/hr
check:
Slower group:
+d%5B1%5D+=+.1429%2A200+
+d%5B1%5D+=+28.58+
Faster group:
+d%5B2%5D+=+.3573%2A200+
+d%5B2%5D+=+71.46+
+d%5B1%5D+%2B+d%5B2%5D+=+28.58+%2B+71.46+
+d%5B1%5D+%2B+d%5B2%5D+=+100.04+
close enough