SOLUTION: Roberta mixed together 20 ounces of tea that costs 3.25 per ounce with an unknown amount of tea that cost 4.50 per ounce. She sold all the mixture at 4.00 per ounce. How many oun

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Question 802167: Roberta mixed together 20 ounces of tea that costs 3.25 per ounce with an unknown amount of tea that cost 4.50 per ounce. She sold all the mixture at 4.00 per ounce.
How many ounces of 4.50 tea did she add if she just broke even?

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Description is equivalent to this:

Roberta mixed U ounces of tea priced L dollars per ounce with unknown v ounces of tea priced H dollars per ounce. The price for the mixture was T dollars per ounce. Solve for v.

Only one starting equation is needed.
highlight%28%28LU%2BHv%29%2F%28U%2Bv%29=T%29

Solving for v is not complicated.
LU%2BHv=T%28U%2Bv%29
LU%2BHv=TU%2BTv
LU%2BHv-Tv=TU
Hv-Tv=TU-LU
v%28H-T%29=%28T-L%29U
highlight%28v=U%28T-L%29%2F%28H-T%29%29

You would plug the values given correspondingly and find the value for v.