SOLUTION: What quantity of 80 per cent acid solution must be mixed with a 20 per cent solution to produce 120 mL of a 50 per cent solution?
-Please explain the steps also, not just the an
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-Please explain the steps also, not just the an
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Question 800405: What quantity of 80 per cent acid solution must be mixed with a 20 per cent solution to produce 120 mL of a 50 per cent solution?
-Please explain the steps also, not just the answer. So I can understand it better :) Found 2 solutions by josmiceli, stanbon:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = ml of 80% solution needed = ml of acid in 80% solution
Let = ml of 20% solution needed = ml of acid in 20% solution
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(1)
(2)
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(2)
(2)
(2)
(2)
Subtract (1) from (2)
(2)
(1)
and, since
(1)
(1)
60 ml of 80% acid solution are needed
check:
(2)
(2)
(2)
(2)
OK
You can put this solution on YOUR website! What quantity of 80 per cent acid solution must be mixed with a 20 per cent solution to produce 120 mL of a 50 per cent solution?
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Equation:
acid + acid = acid
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0.80x + 0.20(120-x) = 0.50*120
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80x + 20*120 - 20x = 50*120
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60x = 30*120
x = 60 mL (amt. of 80% solution needed)
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120-60 = 60 mL (amt. of 20% solution needed)
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Cheers,
Stan H.
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