SOLUTION: My problem is "Suppose you wish to mix 10% acid solution with 24% acid solution to make 10 liters of 14% acid solution. How many liters of each solution should you use?"
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Question 798998: My problem is "Suppose you wish to mix 10% acid solution with 24% acid solution to make 10 liters of 14% acid solution. How many liters of each solution should you use?"
So all I can think to do is .1x+.24x=.14(10) then solve for x but that gives me 4.11 and I can't mix two 4 liter solutions to make 10 liters obviously that makes no sense. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! "Suppose you wish to mix 10% acid solution with 24% acid solution to make 10 liters of 14% acid solution.
How many liters of each solution should you use?"
:
Do it this way,
Let x = amt of 24% solution
then total amt is to e 10 l, therefore
(10-x) = amt of 10% solution
:
A simple mixture equation
.24x + .10(10-x) = .14(10)
