SOLUTION: 1. 100 pounds of candy sells for $1.75 a pound. It contains candy worth $1.65 a pound and some worth $1.90 a pound. How many pounds of each were used?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: 1. 100 pounds of candy sells for $1.75 a pound. It contains candy worth $1.65 a pound and some worth $1.90 a pound. How many pounds of each were used?       Log On

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Question 794695: 1. 100 pounds of candy sells for $1.75 a pound. It contains candy worth $1.65 a pound and some worth $1.90 a pound. How many pounds of each were used?

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
L = $1.65 per pound
H = $1.90 per pound
T = $1.75 per pound
u = how much of the L
v = how much of the H
M = 100 pounds of mixture

%28Lu%2BHv%29%2FM=T and u%2Bv=M
Solve these simultaneous equations for u and v, COMPLETELY in symbols. Once that is done and you have formulas for u and for v, THEN substitute the given values and evaluate u and v.