SOLUTION: how many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20 liters of a 72% solution

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Question 794202: how many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20 liters of a 72% solution
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Extremely common question in general.

u = number of liters of 60%
v = number of liters of 75%

%2860u%2B75v%29%2F20=72 and u%2Bv=20

Solve for u and v.