Question 78749This question is from textbook Elementary Statistics
: Assume that the salaries of elementary school teachers in the United States are normally distributed with a mean of $32,000 and a standard deviation of $3,000. If a teacher is seledcted at random, find the probability that he or she makes more than $36,000.
This question is from textbook Elementary Statistics
Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! Assume that the salaries of elementary school teachers in the United States are
normally distributed with a mean of $32,000 and a standard deviation of $3,000.
If a teacher is seledcted at random, find the probability that he or she makes
more than $36,000.
I'm sorry that statistics course are in a
confusing state of transition between the
two types of tables and the use of the
technology, and that you are a victim of
circumstances.
It depends on what textbook you are using and whether
your teacher is old-fashioned or modern. Different
textbooks have different kinds of normal distribution
tables. Some teachers require you to use tables and
others allow you to use a graphing calculator such as
the TI-83 or TI-84.
I'll try to cover all three methods below:
The answer by calculator is .0912112819. The
answer by tables is .0918. The table is not
as accurate as the calculator.
Here's how to find that on a TI-83 or TI-84.
normalcdf(36000,1E99,32000,3000)
Then press ENTER. You will get the answer
.0912112819.
Here's how to do that on your TI calculator:
To get:
normalcdf(
1. press 2ND
2. press VARS
3. press 2
There is a key for the comma just above the
7 key. To get E (for exponent) press 2ND and
then the comma key.
If you are required to use the tables, then
you calculate the z-score for the left bound
x = 36000:
x - m
z = -------
s/Ön
where m = 32000, s = 3000, n = 1. (There is only one
teacher in the sample.)
z-score for 36000 is calculated thusly:
36000 - 32000
z = --------------- = 1.333333333
3000/Ö1
To use tables you will have to round that off
to 1.33
Some tables have negative numbers and
and some don't.
If your table has negative z-scores,
then you will look up the area to the left
of 1.33 and find it to be .9082.
So you will subtract 1 - .9082 and get .0918
If your table does not have negative z-scores
then you ignore the sign, look up 1.33, and
find .4082. Then you must subtract that from
.5000 and get .5000-.4082 = .0918.
Edwin
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