SOLUTION: I have to use elimination or substitution to solve this. I am able to do that if I can get it into two linear equations in two variables.
The problem is: A chemist has 15% and 4
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-> SOLUTION: I have to use elimination or substitution to solve this. I am able to do that if I can get it into two linear equations in two variables.
The problem is: A chemist has 15% and 4
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Question 782462: I have to use elimination or substitution to solve this. I am able to do that if I can get it into two linear equations in two variables.
The problem is: A chemist has 15% and 40% solutions of acid available. How may liters of each solution should be mixed to obtain 5 liters of a 20% acid solution? Answer by josgarithmetic(39618) (Show Source):
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