SOLUTION: What quantity of 60 per cent acid solution must be mixed with a 30 solution to produce 810 mL of a 50 per cent solution?

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Question 771162: What quantity of 60 per cent acid solution must be mixed with a 30 solution to produce 810 mL of a 50 per cent solution?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Add v mL of 60% acid to u mL of 30% acid solution to produce 810 mL of 50% acid solution.

{amount of just acid}/{amount of resulting solution}={concentration of resulting solution}

%2830u%2B60v%29%2F810=50 AND YOU WILL ALSO NEED highlight%28u%2Bv=810%29

Simplify the rational equation quickly:
%283u%2B6v%29%2F810=5
%28u%2B2v%29%2F270=5
then managing symbols,
u%2B2v=270%2A5
highlight%28u%2B2v=1350%29, easier to work with this form.

The rest left unfinished so you can do the rest. Two equations for the system, highlighted.