SOLUTION: 38. Mixture of Medicine.
The dosage of a medicine ordered by a doctor is 40 milliliters (ml) of a 16% solution. A nurse has available both a 20% solution and a 4% solution of t
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The dosage of a medicine ordered by a doctor is 40 milliliters (ml) of a 16% solution. A nurse has available both a 20% solution and a 4% solution of t
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Question 77099This question is from textbook ALGEBRA Beginning and Intermediate
: 38. Mixture of Medicine.
The dosage of a medicine ordered by a doctor is 40 milliliters (ml) of a 16% solution. A nurse has available both a 20% solution and a 4% solution of this medicine. How many milliliters of each could be mixed to prepare this 40-ml dosage? This question is from textbook ALGEBRA Beginning and Intermediate
You can put this solution on YOUR website! Let x=amount of 4% solution
Then 40-x=amount of 20% solution
Now we know that the amount of pure medicine in the 4% solution (0.04x) plus the amount of pure medicine in the 20% solution 0.20(40-x) must equal the amount of pure medicine in the final solution 0.16(40). So, our equation to solve is:
0.04x+0.20(40-x)=0.16(40) get rid of parens
0.04x+8-0.20x=6.4 subtract 8 from both sides
0.04x+8-8-0.20x=6.4-8 collect like terms
-0.16x=-1.6 divide both sides by -0.16
x=10 ml--------------------------------------amount of 4% solution
40-x=40-10=30 ml-----------------------------amount of 20% solution
CK
0.04(10)+0.20(30)=0.16(40)
0.4+6-6.4
6.4=6.4
