SOLUTION: A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1706 miles required 53 g
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Question 768574: A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1706 miles required 53 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city? Answer by ramkikk66(644) (Show Source):
A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1706 miles required 53 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?
Ans:
Let x miles be driven in the city.
Then miles driven in highway = 1706 - x
Gasolene required for city driving = x/27
Gasolene required for highway = (1706 - x)/38
Total gasoline =
Multiplying by LCM of 27 and 38 which is 1026, to eliminate the denominator
Simplifying and grouping like terms
So miles driven in city = 756
Miles driven in highway = 1706 - 756 = 950
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