SOLUTION: The vat contained 40 liters of a 5 percent salt solution. How much of a 20 percent salt solution should be added to get a 10 percent salt solution?
You can put this solution on YOUR website! The vat contained 40 liters of a 5 percent salt solution. How much of a 20 percent salt solution should be added to get a 10 percent salt solution?
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Let x = amt of 20% solution required
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We know then, that (x+40) will be the final amt.
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A simple equation, (decimals representing the per cent)
.05(40) + .20x = .10(x+40)
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2 + .2x = .1x + 4
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.2x - .1x = 4 - 2
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.1x = 2
x = 2/.1
x = 20 liters of the 20% salt required
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Check: .05(40) + .2(20) = .1(20 + 40)
2 + 4 = .1(60)
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How about this? Did it make sense to you? Any questions?