SOLUTION: How many ounces of a silver alloy that costs $5.50 per ounce should be mixed with one that costs $9.00 per ounce to make a new 30-ounce alloy that costs $7.60 per ounce?

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Question 754290: How many ounces of a silver alloy that costs $5.50 per ounce should be mixed with one that costs $9.00 per ounce to make a new 30-ounce alloy that costs $7.60 per ounce?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
How many ounces,u of a nameOfMetal alloy that costs $L per ounce should be mixed with v ounces that costs $H per ounce to make a new M ounce alloy that costs $T per ounce?

This is the same general mixture problem like so many others of the same form.

highlight%28%28Lu%2BHv%29%2FM=T%29 and highlight%28u%2Bv=M%29
Solve this system for u and v.
Lu%2BHv=TM and from the material balance v=M-u so substitute.
Lu%2BH%28M-u%29=TM
Lu%2BHM-Hu=TM
Lu-Hu=TM-HM
Multiply both sides by negative 1.
Hu-Lu=HM-TM
u%28H-L%29=%28H-T%29%2FM
highlight%28u=M%28H-T%29%2F%28H-L%29%29

and continuation to solve for v will use similar skills.