SOLUTION: A mixture containing 16% of a drug is to be combined with another mixture containing 28% of a drug to obtain 15 ml of a 24% mixture. How much 16% mixture is required?

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Question 753750: A mixture containing 16% of a drug is to be combined with another mixture containing 28% of a drug to obtain 15 ml of a 24% mixture. How much 16% mixture is required?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
(percent mixture wanted) = (amount of pure drug)/(mixture)

Amount of just the drug is 0.16%2Ax%2B0.28%2Ay
Amount of mixture obviously was given, 15 ml.
This uses x for amount of the 16 drug and y for the amount of the 28% drug.

The FRACTION of the mixture as drug we want is 0.24, which means same as 24%.

Put everything in place:
%280.16x%2B0.28y%29%2F15=0.24 AND x%2By=15
Solving this system should not be any trouble.